2013年12月19日星期四

Microsoft 070-461 originale fragen

Es ist Ihnen weis, Pass4Test zu wählen, um die Microsoft 070-461 Zertifizierungsprüfung zu bestehen. Sie können im Internet teilweise die Fragen und Antworten zur Microsoft 070-461 Zertifizierungsprüfung von Pass4Test kostenlos herunterladen. Dann werden Sie mehr Vertrauen in unsere Produkte haben. Sie können sich dann gut auf Ihre Microsoft 070-461 Zertifizierungsprüfung vorbereiten. Für den Fall in der Prüfung, zahlen wir Ihnen die gesammte Summe zurück.

Pass4Test ist eine Website, die Bedürfnisse der Kunden abdecken können. Diejenigen, die unsere Simulationssoftware zur IT-Zertifizierungsprüfung benutzt und die Prüfung betanden haben, sind unsere Stammgäste geworden. Pass4Test steht Ihne die fortschrittliche Ausbildungstechnik zur Verfügung, die Ihnen beim Bestehen der Microsoft 070-461 Zertifizierungsprüfung hilft.

Exam Code: 070-461
Prüfungsname: Querying Microsoft SQL Server 2012
Aktulisiert: 2013-12-19
Nummer: 98 Q&As

Die Schulungsunterlagen von Pass4Test ist unvergleichbar im Vergleich zu anderen Websites. Sie sind extrem real und richitig. Um den Kandidaten zum Bestehen der Prüfung zu verhelfen, hat unser IT-Eliteexpertentem immer noch Untersuchungen gemacht. Die Produkte von Pass4Test sind nicht nur real, sondern auch kostengünstig. Wenn Sie unsere Prüdukte wählen, können Sie einen einjährigen kostenlosen Update-Service bekommen. Sie können sich genügend auf die Prüfung vorbereiten und den Stress überwinden. Das ist wirklich eine gute Wahl.

Es ist uns allen bekannt, dass IT-Branche eine neue Branche und auch eine Kette, die die wirtschaftliche Entwicklung fördert, ist. So ist ihre Position nicht zu ignorieren. Die IT-Zertifizierung ist eine Methode für den Wettbewerb. Durch die Zertifizierung werden Sie sich in allen Aspekten verbessern. Aber es ist nicht so einfach, die Prüfung zu bestehen. So empfehle ich Ihnen unsere Schulungsinstrumente. Wenn Sie die Schulungsressourcen wählen, ist Pass4Test die erste Wahl. Seine Erfolgsquote beträgt 100%. Und Sie können die Prüfung sicher bestehen.

Ein wunderbares Leben ist es, dass man sich wagt, nach etwas zu trachten. Wenn Sie eines Tages in einem wackligen Stuhl sitzt und Ihre Vergangenheit erinnern, können Sie einfach lächern. Das bedeutet, dass Ihr Leben erfolgreich ist. Wollen Sie ein erfolgreiches Leben führen?Dann benutzen Sie doch die Schulungsunterlagen zur Microsoft 070-461-Prüfung von Pass4Test, die Fragen und Antworten beinhalten und jedem Kandidaten sehr passen. Ihre Erfolgsquote beträgt 100%. Sie sollen Pass4Test so schnell wie möglich kaufen.

070-461 prüfungsfragen Demo kostenlos downloden: http://www.pass4test.de/070-461.html

NO.1 You develop a Microsoft SQL Server 2012 server database that supports an application. The application
contains a table that has the following definition:
CREATE TABLE Inventory
(ItemID int NOT NULL PRIMARY KEY,
ItemsInStore int NOT NULL,
ItemsInWarehouse int NOT NULL)
You need to create a computed column that returns the sum total of the ItemsInStore and
ItemsInWarehouse values for each row.
The new column is expected to be queried heavily, and you need to be able to index the column.
Which Transact-SQL statement should you use?
A. ALTER TABLE Inventory
All TotalItems AS Item3lnStore + ItemsInWarehouse
B. ALTER TABLE Inventory
ADD TotalItems AS ItemsInStore + ItemsInWarehouse PERSISTED
C. ALTER TABLE Inventory
ADD TotalItems AS SUM (ItemsInStore, ItemsInWarehouse) PERSISTED
D. ALTER TABLE Inventory
All TotalItems AS SUM (ItemsInStore, ItemsInWarehouse)
Answer: C

Microsoft   070-461 zertifizierung   070-461   070-461   070-461   070-461

NO.2 You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown
in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to
1 in the following XML format.
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers-CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers=CustomerId = 1
FOR XML RAW, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerXd - Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId- 1
FOR XML AUTO
F.SELECT Name, Country, Crderld, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
H. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount
FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
Answer: D

Microsoft echte fragen   070-461   070-461   070-461

NO.3 DRAG DROP
You use a Microsoft SQL Server 2012 database.
You need to create an indexed view within the database for a report that displays Customer Name and the
total revenue for that customer.
Which four T-SQL statements should you use? (To answer, move the appropriate SQL statements from
the list of statements to the answer area and arrange them in the correct order.)
Answer:

NO.4 You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown
in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to
1 in the following XML format.
<row OrderId= "1" orderDate="2000-01-01T00:00:00", Amount="3400.00" Name="Customer A"
Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer A"
Country-"Australia" />
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers-CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers=CustomerId = 1
FOR XML RAW, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId- 1
FOR XML AUTO
F. SELECT Name, Country, Crderld, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
H. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount
FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
Answer: A

Microsoft antworten   070-461   070-461 prüfungsfragen   070-461   070-461

NO.5 You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown
in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to
1 in the following XML format.
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers-CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers=CustomerId = 1
FOR XML RAW, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerXd - Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId- 1
FOR XML AUTO
F.SELECT Name, Country, Crderld, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
H. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount
FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
Answer: E

Microsoft originale fragen   070-461   070-461

NO.6 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the top half of the students arranged by their average marks must be given a rank
of 1 and the remaining students must be given a rank of 2.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code,
DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value
FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: D

Microsoft prüfungsfragen   070-461 prüfungsunterlagen   070-461   070-461

NO.7 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects.
You need to retrieve the students who scored the highest marks for each subject along with the marks.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code,
DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value
FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: F

Microsoft zertifizierung   070-461 zertifizierungsfragen   070-461 originale fragen   070-461

NO.8 You develop a Microsoft SQL Server 2012 database that contains a table named Customers.
The Customers table has the following definition:
You need to create an audit record only when either the MobileNumber or HomeNumber column is
updated.
Which Transact-SQL query should you use?
A. CREATE TRIGGER TrgPhoneNumberChange
ON Customers FOR UPDATE
AS
IF COLUMNS_UPDATED (HomeNumber, MobiieNumber)
- - Create Audit Records
B. CREATE TRIGGER TrgPhoneNumberChange
ON Customers FOR UPDATE
AS
IF EXISTS( SELECT HomeNumber from inserted) OR
EXISTS (SELECT MobileNumber FROM inserted)
- - Create Audit Records
C. CREATE TRIGGER TrgPhoneNumberChange
ON Customers FOR UPDATE
AS
IF COLUMNS_CHANGED (HomeNumber, MobileNumber)
- - Create Audit Records
D. CREATE TRIGGER TrgPhoneNumberChange
ON Customers FOR UPDATE
AS
IF UPDATE (HomeNumber) OR UPDATE (MobileNumber)
- - Create Audit Records
Answer: D

Microsoft   070-461   070-461

NO.9 You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown
in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerIdvalue set to
1 in the following XML format.
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers-CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers=CustomerId = 1
FOR XML RAW, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerXd - Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId- 1
FOR XML AUTO
F. SELECT Name, Country, Crderld, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
H. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount
FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
Answer: C

Microsoft prüfungsfragen   070-461 antworten   070-461 dumps   070-461 antworten   070-461 prüfung

NO.10 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
Students must be ranked based on their average marks.
If one or more students have the same average, the same rank must be given to these students.
Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code,
DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value
FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: A

Microsoft prüfungsfrage   070-461 testantworten   070-461

Pass4Test bietet Ihnen die neusten 00M-654 exam Unterlagen und 700-505 pdf Fragen & Antworten mit hoher Qualität. Unser HP2-N35 zertifizierung und BAS-004 prüfung Lernführung können Ihnen hilfen, die aktuellen Prüfungen zu bestehen. Hochqualitative MB7-702 dumps Training Unterlagen können Ihnen gewährleisten, leichter und schneller, diese Prüfung zu bestehen. Es ist sehr einfach für Sie, die Zertifizierung zu bekommen.

Artikel Link: http://www.pass4test.de/070-461.html

没有评论:

发表评论